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Russian Roulette


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Poll: Russian Roulette (15 member(s) have cast votes)

Given the parameters described, how many times would you squeeze the trigger?

  1. One (6 votes [40.00%])

    Percentage of vote: 40.00%

  2. Two (1 votes [6.67%])

    Percentage of vote: 6.67%

  3. Three (0 votes [0.00%])

    Percentage of vote: 0.00%

  4. Four (0 votes [0.00%])

    Percentage of vote: 0.00%

  5. Five (0 votes [0.00%])

    Percentage of vote: 0.00%

  6. Six (I don't understand how math works) (0 votes [0.00%])

    Percentage of vote: 0.00%

  7. Zero — I wouldn't play (8 votes [53.33%])

    Percentage of vote: 53.33%

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#1 ᗅᗺᗷᗅ

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Posted 29 October 2013 - 05:40 PM

The game is simple:

 

You have a six-shot revolver.  One chamber is loaded, the rest are empty.  You do not know which is which.  If you put the gun to your temple and squeeze the trigger (and survive), you will receive $1 million.  You will receive a further $1 million for each successive squeeze of the trigger, up to a possible $5 million.  Or you could blow your brains out.

 

How many times do you squeeze the trigger?





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#2 GeniusInc

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Posted 29 October 2013 - 05:56 PM

2 max.



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#3 Thrash

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Posted 29 October 2013 - 06:05 PM

1



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#4 ᗅᗺᗷᗅ

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Posted 29 October 2013 - 06:17 PM

In case anyone wants the math:

 

On the first squeeze, there is a 16.67% chance that you will die.

 

On the second squeeze, 20%.

 

Third squeeze, 25%.

 

Fourth squeeze, 33.33%.

 

Fifth squeeze, 50%.

 

And on the sixth squeeze, if you've somehow managed to survive up to now... well, you know.



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#5 GeniusInc

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Posted 29 October 2013 - 06:22 PM

In case anyone wants the math:

 

On the first squeeze, there is a 16.67% chance that you will die.

 

On the second squeeze, 20%.

 

Third squeeze, 25%.

 

Fourth squeeze, 33.33%.

 

Fifth squeeze, 50%.

 

And on the sixth squeeze, if you've somehow managed to survive up to now... well, you know.

 

 

Your math is all screwed up

 

you have a 1/6 then a 2/6 then a 3/6 and so on

thats 16.67% then ~33% then 50% then ~66% then 84% then 100%



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#6 PrinceVegeta

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Posted 29 October 2013 - 07:02 PM

Just once.



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#7 King Biscuit

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Posted 29 October 2013 - 08:29 PM

Not at all.



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#8 rotty

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Posted 29 October 2013 - 09:02 PM

Im kind of in shock that an anti-hand gun guy would make such a thread.  :|



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#9 King Biscuit

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Posted 29 October 2013 - 10:35 PM

Im kind of in shock that an anti-hand gun guy would make such a thread.  :|

 

Yeah I found that odd too.



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#10 Justavictim82

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Posted 30 October 2013 - 12:14 AM

I would pull it once. Only for the oppertunity to provide financial security for my family.

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#11 Jon32492

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Posted 30 October 2013 - 01:12 AM

In case anyone wants the math:

 

On the first squeeze, there is a 16.67% chance that you will die.

 

On the second squeeze, 20%.

 

Third squeeze, 25%.

 

Fourth squeeze, 33.33%.

 

Fifth squeeze, 50%.

 

And on the sixth squeeze, if you've somehow managed to survive up to now... well, you know.

 

 

Your math is all screwed up

 

you have a 1/6 then a 2/6 then a 3/6 and so on

thats 16.67% then ~33% then 50% then ~66% then 84% then 100%

 

No, because once you pull, those chambers are no longer counted. So, more like 1/6, then 1/5, then 1/4, then 1/3, then 1/2, then dead. This is the chance on each squeeze that the bullet will be there. I think you calculated the chance of you being dead by the time you got to that shot.

 

But given my luck, it'd be more like 6/6, 5/5, 4/4, 3/3, 2/2, 1/1. So, I would not play. lol.



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#12 Redezra

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Posted 31 October 2013 - 12:50 AM

Nope~ I don't like guns.



#13 Manoka

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Posted 31 October 2013 - 05:47 AM

Becuase the amount would increase exponentially each time I pulled, I would do it just once, to give me the best odds.

 

Since I know a bit about guns I'd cheat though.



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#14 ᗅᗺᗷᗅ

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Posted 31 October 2013 - 06:54 AM

Your math is all screwed up

 

Not at all.  On the first shot there is a 1 in 6 chance that you will get the bullet, or a 16.67% chance.  On the second shot, however, your chances increase, because you've already eliminated one chamber, so the bullet must be in one of the remaining five, for a 1 in 5 chance (20%).  After two squeezes you are down to the bullet being in one of four chambers (25% chance), then one of three (33.33% chance), two (50% chance), and, finally, one, for a 100% chance that you will blow your brains out.

 

MATH!  :)



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#15 Manoka

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Posted 31 October 2013 - 09:07 AM

That's why I'd use a Ruger Blackhawk, since it has 8 cylinders! :D



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